AQA GCSE Combined Science: Trilogy · 6.6

Waves

50 revision questions with answers for 6.6 Waves in AQA GCSE Combined Science: Trilogy (spec 8464). Practise with flashcards, a topic quiz, a random quiz across the course, 5 crosswords, or read every question and answer below. Not official AQA material.

All 50 questions and answers

  1. Question 1 · Spec 6.6.1.1

    What is a transverse wave?

    Answer:
    A wave in which oscillations are perpendicular to the direction of energy transfer.
  2. Question 2 · Spec 6.6.1.1

    What is a longitudinal wave?

    Answer:
    A wave in which oscillations are parallel to the direction of energy transfer.
  3. Question 3 · Spec 6.6.1.1

    Give one transverse and one longitudinal wave example.

    Answer:
    Water-surface ripples are modelled as transverse; sound in air is longitudinal.
  4. Question 4 · Spec 6.6.1.1

    What are compressions and rarefactions?

    Answer:
    Compressions are regions where particles are closer together; rarefactions are regions where particles are farther apart.
  5. Question 5 · Spec 6.6.1.1

    How can a floating object show that waves do not carry the water along overall?

    Answer:
    It oscillates around its position as ripples pass, while the wave transfers energy across the surface.
  6. Question 6 · Spec 6.6.1.2

    Define amplitude.

    Answer:
    The maximum displacement of a point from its undisturbed position.
  7. Question 7 · Spec 6.6.1.2

    Define wavelength.

    Answer:
    The distance between corresponding points on neighbouring waves, such as crest to crest or compression to compression.
  8. Question 8 · Spec 6.6.1.2

    Define frequency and give its unit.

    Answer:
    The number of complete waves passing a point each second, measured in hertz, Hz.
  9. Question 9 · Spec 6.6.1.2

    Define period and state its equation.

    Answer:
    The time for one complete oscillation. T = 1/f.
  10. Question 10 · Spec 6.6.1.2

    A wave has frequency 50 Hz. Find its period.

    Answer:
    T = 1 / 50 = 0.020 s.
  11. Question 11 · Spec 6.6.1.2

    State the wave-speed equation.

    Answer:
    v = f x wavelength; speed in m/s, frequency in Hz and wavelength in m.
  12. Question 12 · Spec 6.6.1.2

    Find the speed of a wave with frequency 4.0 Hz and wavelength 0.75 m.

    Answer:
    v = 4.0 × 0.75 = 3.0 m/s.
  13. Question 13 · Spec 6.6.1.2

    Sound travels at 330 m/s at 660 Hz. Find wavelength.

    Answer:
    Wavelength = speed / frequency = 330 / 660 = 0.50 m.
  14. Question 14 · Spec 6.6.1.2

    At fixed wave speed, what happens to wavelength when frequency doubles?

    Answer:
    Wavelength halves, because speed = frequency x wavelength.
  15. Question 15 · Spec 6.6.1.2 · Required practical

    How can ripple-tank wavelength be measured more accurately?

    Answer:
    Measure across several complete wavelengths in a clear pattern and divide by their number, accounting for image scale if projected.
  16. Question 16 · Spec 6.6.1.2 · Required practical

    How can ripple-tank wave speed be calculated?

    Answer:
    Measure wavelength and use the known or measured frequency, then calculate v = f x wavelength.
  17. Question 17 · Spec 6.6.1.2 · Required practical

    How can waves in a solid string be used to measure wavelength?

    Answer:
    Produce a steady wave pattern and measure distances between equivalent points; for a standing pattern, adjacent nodes are half a wavelength apart.
  18. Question 18 · Spec 6.6.1.2

    How can the speed of sound in air be measured with two microphones?

    Answer:
    Measure their separation and the time delay between the same sound reaching them; calculate speed = distance / time.
  19. Question 19 · Spec 6.6.1.2

    Why can increasing microphone separation reduce relative timing uncertainty?

    Answer:
    The travel time is longer, so a fixed timing uncertainty is a smaller fraction of the measurement.
  20. Question 20 · Spec 6.6.2.1

    What do all electromagnetic waves have in common?

    Answer:
    They are transverse, transfer energy and travel at the same speed in a vacuum.
  21. Question 21 · Spec 6.6.2.1

    List the electromagnetic spectrum from longest to shortest wavelength.

    Answer:
    Radio, microwaves, infrared, visible light, ultraviolet, X-rays, gamma rays.
  22. Question 22 · Spec 6.6.2.1

    How does frequency change from radio waves to gamma rays?

    Answer:
    It increases as wavelength decreases.
  23. Question 23 · Spec 6.6.2.1

    Which part of the spectrum can human eyes detect?

    Answer:
    Visible light, from red at longer wavelengths to violet at shorter wavelengths.
  24. Question 24 · Spec 6.6.2.1

    What is the approximate speed of electromagnetic waves in a vacuum?

    Answer:
    3.0 × 10⁸ m/s.
  25. Question 25 · Spec 6.6.2.1

    An electromagnetic wave has wavelength 0.10 m. Use v = 3.0 × 10⁸ m/s to find frequency.

    Answer:
    f = v / wavelength = 3.0 × 10⁹ Hz.
  26. Question 26 · Spec 6.6.2.2

    How should a ray diagram show refraction into a medium where the ray bends towards the normal?

    Answer:
    Draw the normal perpendicular to the boundary and show the refracted ray at a smaller angle to it than the incident ray.
  27. Question 27 · Spec 6.6.2.2 · Higher only

    Why does refraction occur when a wave crosses obliquely into a different medium?

    Answer:
    Its speed changes at the boundary, so different parts of the wavefront change speed at different times, changing direction.
  28. Question 28 · Spec 6.6.2.2 · Higher only

    What happens to speed, wavelength and frequency when light enters a slower medium?

    Answer:
    Speed and wavelength decrease; frequency remains unchanged.
  29. Question 29 · Spec 6.6.2.2 · Higher only

    Why can the same material transmit one electromagnetic wavelength but absorb another?

    Answer:
    Its interaction with electromagnetic radiation depends on wavelength.
  30. Question 30 · Spec 6.6.2.2 · Required practical

    How can infrared absorption by surfaces be compared?

    Answer:
    Expose comparable differently finished surfaces to the same infrared source; measure temperature rise while controlling distance, time and starting temperature.
  31. Question 31 · Spec 6.6.2.2 · Required practical

    Which surfaces are usually good infrared absorbers and emitters?

    Answer:
    Dark, matt surfaces; shiny, light surfaces are generally poorer absorbers and emitters.
  32. Question 32 · Spec 6.6.2.2 · Required practical

    How can emission from different surfaces of a Leslie cube be compared?

    Answer:
    Fill it with hot water and compare detector readings at equal distances from each face, using the same angle and conditions.
  33. Question 33 · Spec 6.6.2.2 · Required practical

    Why keep an infrared detector the same distance from each test surface?

    Answer:
    Detected radiation changes with distance, so unequal distances would confound the surface comparison.
  34. Question 34 · Spec 6.6.2.3 · Higher only

    How can radio waves be generated?

    Answer:
    By oscillations in electrical circuits.
  35. Question 35 · Spec 6.6.2.3 · Higher only

    What can happen when radio waves are absorbed by an aerial circuit?

    Answer:
    They can induce an alternating current with the same frequency as the incoming radio wave.
  36. Question 36 · Spec 6.6.2.3

    How can atoms generate or absorb electromagnetic waves?

    Answer:
    Changes in electron energy levels can emit or absorb radiation; nuclear changes can generate gamma rays.
  37. Question 37 · Spec 6.6.2.3

    What health effects can excessive ultraviolet exposure cause?

    Answer:
    Premature skin ageing and increased risk of skin cancer.
  38. Question 38 · Spec 6.6.2.3

    Why can X-rays and gamma rays increase cancer risk?

    Answer:
    They are ionising and can damage DNA, causing mutations that may lead to cancer.
  39. Question 39 · Spec 6.6.2.3

    What two factors affect the hazard from electromagnetic exposure?

    Answer:
    The type of radiation and the dose received; exposure conditions also affect the risk.
  40. Question 40 · Spec 6.6.2.3

    Given 1 Sv = 1,000 mSv, convert 0.025 Sv to mSv.

    Answer:
    0.025 × 1,000 = 25 mSv. The conversion is supplied; recalling the dose unit is not required.
  41. Question 41 · Spec 6.6.2.4

    Give a common use of radio waves.

    Answer:
    Radio and television communication.
  42. Question 42 · Spec 6.6.2.4

    Give two common uses of microwaves.

    Answer:
    Satellite communications and cooking food.
  43. Question 43 · Spec 6.6.2.4

    Give three uses of infrared radiation.

    Answer:
    Electrical heaters, cooking food and infrared cameras.
  44. Question 44 · Spec 6.6.2.4

    Give a communication use of visible light.

    Answer:
    Fibre-optic communication.
  45. Question 45 · Spec 6.6.2.4

    Give two listed uses of ultraviolet radiation.

    Answer:
    Energy-efficient lamps and sun tanning.
  46. Question 46 · Spec 6.6.2.4

    Give uses of X-rays and gamma rays.

    Answer:
    Medical imaging and medical treatments.
  47. Question 47 · Spec 6.6.2.4 · Higher only

    Why are microwaves suitable for satellite communications?

    Answer:
    They can pass through the atmosphere to communicate with satellites.
  48. Question 48 · Spec 6.6.2.4 · Higher only

    Why are infrared cameras useful for observing warm objects?

    Answer:
    Warm objects emit infrared radiation; detecting it reveals temperature differences even without visible illumination.
  49. Question 49 · Spec 6.6.2.4 · Higher only

    Why are X-rays useful in imaging bones?

    Answer:
    They pass through soft tissue more readily than through bone, producing a contrast pattern at the detector.
  50. Question 50 · Spec 6.6.2.4 · Higher only

    Why can gamma radiation be useful in cancer treatment?

    Answer:
    Its ionising effect can kill cancer cells, although exposure must be directed to limit damage to healthy tissue.

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