AQA GCSE Combined Science: Trilogy · 5.5

Energy changes

50 revision questions with answers for 5.5 Energy changes in AQA GCSE Combined Science: Trilogy (spec 8464). Practise with flashcards, a topic quiz, a random quiz across the course, 5 crosswords, or read every question and answer below. Not official AQA material.

All 50 questions and answers

  1. Question 1 · Spec 5.5.1.1

    What is an exothermic reaction?

    Answer:
    A reaction that transfers energy to the surroundings, increasing their temperature.
  2. Question 2 · Spec 5.5.1.1

    What is an endothermic reaction?

    Answer:
    A reaction that takes in energy from the surroundings, decreasing their temperature.
  3. Question 3 · Spec 5.5.1.1

    How is energy conserved during an exothermic reaction?

    Answer:
    Energy lost by the reacting system is transferred to the surroundings; the total energy remains unchanged.
  4. Question 4 · Spec 5.5.1.1

    A reaction mixture warms without external heating. What does this suggest?

    Answer:
    The reaction is exothermic: energy is transferred to the mixture and surroundings.
  5. Question 5 · Spec 5.5.1.1

    A reaction mixture cools below its initial temperature. What does this suggest?

    Answer:
    The reaction is endothermic: energy is taken in from the mixture and surroundings.
  6. Question 6 · Spec 5.5.1.1

    Name three common exothermic reaction types.

    Answer:
    Combustion, many oxidation reactions and neutralisation.
  7. Question 7 · Spec 5.5.1.1

    Give two examples of endothermic reactions.

    Answer:
    Thermal decomposition and the reaction between citric acid and sodium hydrogencarbonate.
  8. Question 8 · Spec 5.5.1.1

    Why are exothermic reactions useful in hand warmers?

    Answer:
    They transfer energy to the surroundings, warming the user's hands.
  9. Question 9 · Spec 5.5.1.1

    Why can an endothermic reaction be useful in a sports injury pack?

    Answer:
    It absorbs energy from the surroundings, cooling the injured area.
  10. Question 10 · Spec 5.5.1.1

    What evidence would help evaluate a self-heating can?

    Answer:
    Temperature rise, time to reach a useful temperature, heating duration, cost and risks such as excessive temperatures or leakage.
  11. Question 11 · Spec 5.5.1.1 · Required practical

    Suggest an independent variable for the temperature-change practical.

    Answer:
    The concentration of one reacting solution, while controlling the other reactant and measurement conditions.
  12. Question 12 · Spec 5.5.1.1 · Required practical

    What is the dependent variable when comparing reaction heating effects?

    Answer:
    The temperature change of the reaction mixture.
  13. Question 13 · Spec 5.5.1.1 · Required practical

    Which variables should be controlled when testing concentration's effect?

    Answer:
    Solution volumes, initial temperature, other reactant amount, container and mixing method.
  14. Question 14 · Spec 5.5.1.1 · Required practical

    Why use an insulated cup rather than an uninsulated metal container?

    Answer:
    It reduces energy transfer to the surroundings, giving a temperature change closer to that caused by the reaction.
  15. Question 15 · Spec 5.5.1.1 · Required practical

    Why can a lid improve a temperature-change investigation?

    Answer:
    It reduces energy transfer to the surroundings, including loss through evaporation.
  16. Question 16 · Spec 5.5.1.1 · Required practical

    Why should the mixture be stirred gently before reading temperature?

    Answer:
    Stirring makes temperature more uniform, so the thermometer samples the mixture more representatively.
  17. Question 17 · Spec 5.5.1.1 · Required practical

    Why record the highest or lowest temperature reached?

    Answer:
    The mixture later exchanges energy with the surroundings, reducing the observed change from the reaction.
  18. Question 18 · Spec 5.5.1.1 · Required practical

    What does thermometer resolution mean?

    Answer:
    The smallest temperature change that the thermometer can display or its scale can distinguish.
  19. Question 19 · Spec 5.5.1.1 · Required practical

    Outline a method for measuring neutralisation's temperature change.

    Answer:
    Measure equal starting temperatures, mix measured acid and alkali volumes in an insulated cup, stir and record the maximum temperature.
  20. Question 20 · Spec 5.5.1.1 · Required practical

    A mixture warms from 19.5 °C to 27.0 °C. Calculate temperature change.

    Answer:
    Temperature change = 27.0 − 19.5 = +7.5 °C; the warming suggests an exothermic reaction.
  21. Question 21 · Spec 5.5.1.1 · Required practical

    A mixture cools from 22.0 °C to 16.5 °C. Calculate temperature change.

    Answer:
    Temperature change = 16.5 − 22.0 = -5.5 °C; the cooling suggests an endothermic reaction.
  22. Question 22 · Spec 5.5.1.1 · Required practical

    Temperature rises are 6.1, 6.3 and 6.2 °C. Find the mean.

    Answer:
    Mean rise = (6.1 + 6.3 + 6.2) / 3 = 6.2 °C.
  23. Question 23 · Spec 5.5.1.1 · Required practical

    Temperature rises range from 5.8 to 6.4 °C. Find their range.

    Answer:
    Range = 6.4 − 5.8 = 0.6 °C.
  24. Question 24 · Spec 5.5.1.1 · Required practical

    One temperature rise is much lower than the repeats. What should be checked?

    Answer:
    Check quantities, initial temperatures, mixing, timing and possible energy losses; repeat before deciding whether exclusion is justified.
  25. Question 25 · Spec 5.5.1.1 · Required practical

    Why should reactants start at the same temperature in a comparison?

    Answer:
    Otherwise initial temperature differences could affect the measured change independently of the reaction variable.
  26. Question 26 · Spec 5.5.1.1 · Required practical

    Why is comparing temperature rises unfair if solution volumes differ greatly?

    Answer:
    Different amounts of solution need different amounts of energy for the same temperature rise, so volume becomes a confounding variable.
  27. Question 27 · Spec 5.5.1.1 · Required practical

    Suggest a concentration hypothesis for neutralisation with the other reactant in excess.

    Answer:
    At fixed volumes, a higher acid concentration may produce a larger temperature rise because more acid reacts.
  28. Question 28 · Spec 5.5.1.1 · Required practical

    Why can a temperature-time graph improve the record of a reaction?

    Answer:
    It shows the initial temperature, rise or fall and later return towards room temperature, helping identify the extreme value.
  29. Question 29 · Spec 5.5.1.1 · Required practical

    Why might a no-reaction control be useful in a temperature investigation?

    Answer:
    It shows temperature drift caused by mixing or surroundings rather than the intended chemical reaction.
  30. Question 30 · Spec 5.5.1.1 · Required practical

    Why does energy loss usually make an exothermic temperature rise too small?

    Answer:
    Some released energy leaves the mixture before measurement, so less remains to raise its temperature.
  31. Question 31 · Spec 5.5.1.2

    What are the axes on a reaction profile?

    Answer:
    Vertical: energy. Horizontal: progress of the reaction, not time.
  32. Question 32 · Spec 5.5.1.2

    Where are reactants and products shown on a reaction profile?

    Answer:
    Reactants are at the starting energy level; products are at the finishing energy level.
  33. Question 33 · Spec 5.5.1.2

    How does an exothermic reaction profile show energy transfer?

    Answer:
    The products lie at a lower energy level than the reactants.
  34. Question 34 · Spec 5.5.1.2

    How does an endothermic reaction profile show energy transfer?

    Answer:
    The products lie at a higher energy level than the reactants.
  35. Question 35 · Spec 5.5.1.2

    Define activation energy.

    Answer:
    The minimum energy that colliding particles must have for a reaction to occur.
  36. Question 36 · Spec 5.5.1.2

    Where is activation energy shown on a reaction profile?

    Answer:
    The vertical energy difference from the reactant level to the top of the curve.
  37. Question 37 · Spec 5.5.1.2

    Why may a fuel need a spark even though combustion is exothermic?

    Answer:
    The spark supplies energy to overcome the activation-energy barrier and start the reaction.
  38. Question 38 · Spec 5.5.1.2

    Which profile feature identifies overall energy change?

    Answer:
    The vertical difference between reactant and product energy levels, rather than the height of the peak alone.
  39. Question 39 · Spec 5.5.1.2

    Does a higher activation-energy peak mean a reaction is more exothermic?

    Answer:
    No. Exothermicity depends on the difference between reactant and product levels, not the peak's height.
  40. Question 40 · Spec 5.5.1.2

    Can you read reaction duration directly from a reaction profile?

    Answer:
    No. Its horizontal axis is reaction progress, so it does not provide a time scale.
  41. Question 41 · Spec 5.5.1.3 · Higher only

    Is bond breaking exothermic or endothermic?

    Answer:
    Endothermic: energy must be supplied to break a bond.
  42. Question 42 · Spec 5.5.1.3 · Higher only

    Is bond formation exothermic or endothermic?

    Answer:
    Exothermic: energy is released when bonds form.
  43. Question 43 · Spec 5.5.1.3 · Higher only

    State the bond-energy calculation for overall energy change.

    Answer:
    Energy change = total energy needed to break reactant bonds - total energy released forming product bonds.
  44. Question 44 · Spec 5.5.1.3 · Higher only

    Explain an exothermic reaction in terms of bond energies.

    Answer:
    Forming product bonds releases more energy than is needed to break reactant bonds.
  45. Question 45 · Spec 5.5.1.3 · Higher only

    Explain an endothermic reaction in terms of bond energies.

    Answer:
    Breaking reactant bonds requires more energy than forming product bonds releases.
  46. Question 46 · Spec 5.5.1.3 · Higher only

    Breaking bonds requires 900 kJ/mol and forming bonds releases 1,200 kJ/mol. Find the change.

    Answer:
    900 − 1,200 = -300 kJ/mol; the reaction is exothermic.
  47. Question 47 · Spec 5.5.1.3 · Higher only

    Breaking bonds requires 1,100 kJ/mol and forming bonds releases 850 kJ/mol. Find the change.

    Answer:
    1,100 − 850 = +250 kJ/mol; the reaction is endothermic.
  48. Question 48 · Spec 5.5.1.3 · Higher only

    H₂ + Cl₂ → 2HCl. Bond energies: H-H 436, Cl-Cl 243, H-Cl 431 kJ/mol. Calculate the change.

    Answer:
    Broken: 436 + 243 = 679. Formed: 2 × 431 = 862. Change = -183 kJ/mol.
  49. Question 49 · Spec 5.5.1.3 · Higher only

    2H₂ + O₂ → 2H₂O. Bond energies: H-H 436, O=O 498, O-H 464 kJ/mol. Calculate the change for the equation.

    Answer:
    Broken: 2 × 436 + 498 = 1,370. Formed: 4 × 464 = 1,856. Change = -486 kJ per equation as written.
  50. Question 50 · Spec 5.5.1.3 · Higher only

    Why must coefficients be considered in bond-energy calculations?

    Answer:
    They determine the number of molecules and therefore the total number of each bond broken or formed.

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