Pearson Edexcel GCSE Combined Science · P13

Electromagnetic induction

50 revision questions with answers for P13 Electromagnetic induction in Pearson Edexcel GCSE Combined Science (spec 1SC0). Practise with flashcards, a topic quiz, a random quiz across the course, 5 crosswords, or read every question and answer below. Not official Pearson material.

All 50 questions and answers

  1. Question 1 · Spec P13.2 · Higher only

    What is electromagnetic induction in the situations studied?

    Answer:
    A changing magnetic field through a circuit produces a potential difference.
  2. Question 2 · Spec P13.2 · Higher only

    How can moving a magnet relative to a coil induce a voltage?

    Answer:
    Movement changes the magnetic field linking the coil.
  3. Question 3 · Spec P13.2 · Higher only

    Why does a stationary magnet usually give no induced voltage in a stationary coil?

    Answer:
    The magnetic field linking the coil is not changing.
  4. Question 4 · Spec P13.2 · Higher only

    How does faster relative motion affect induced potential difference?

    Answer:
    It increases the field's rate of change, usually increasing the induced voltage.
  5. Question 5 · Spec P13.2 · Higher only

    How can a stronger magnet affect induced voltage for the same motion?

    Answer:
    It generally increases the voltage because the field change is greater.
  6. Question 6 · Spec P13.2 · Higher only

    How can more coil turns affect the induced voltage?

    Answer:
    More turns experience the changing field, increasing the total induced voltage.
  7. Question 7 · Spec P13.2 · Higher only

    What happens to induced voltage if the magnet's motion reverses?

    Answer:
    Its polarity reverses, with other conditions unchanged.
  8. Question 8 · Spec P13.2 · Higher only

    What happens if the approaching magnet's pole is reversed?

    Answer:
    The induced voltage polarity reverses.
  9. Question 9 · Spec P13.2 · Higher only

    What happens if both the moving direction and magnet pole reverse?

    Answer:
    The induced polarity stays the same as before, for otherwise comparable motion.
  10. Question 10 · Spec P13.2 · Higher only

    How does the induced current's magnetic field relate to the original change?

    Answer:
    It opposes the change that produced it.
  11. Question 11 · Spec P13.2 · Higher only

    A north pole approaches a conducting coil. What effect does the induced field have?

    Answer:
    It opposes the approach; the near coil end acts as a north pole.
  12. Question 12 · Spec P13.2 · Higher only

    A north pole is withdrawn from a conducting coil. What effect does the induced field have?

    Answer:
    It opposes withdrawal; the near coil end acts as a south pole.
  13. Question 13 · Spec P13.2 · Higher only

    Does the induced field always oppose the original magnetic field?

    Answer:
    No. It opposes the change, so it can reinforce a decreasing field or oppose an increasing one.
  14. Question 14 · Spec P13.2 · Higher only

    When can an induced potential difference produce a sustained current while the field changes?

    Answer:
    When the conducting circuit is closed.
  15. Question 15 · Spec P13.5 · Higher only

    What does the primary coil do in a transformer?

    Answer:
    Its alternating current creates a changing magnetic field.
  16. Question 16 · Spec P13.5 · Higher only

    How does the secondary coil receive energy without a direct electrical connection?

    Answer:
    The changing magnetic field links it and induces an alternating potential difference, driving current in a closed secondary circuit.
  17. Question 17 · Spec P13.5 · Higher only

    Why is alternating current suitable for transformer operation?

    Answer:
    It continually changes the magnetic field linking the coils.
  18. Question 18 · Spec P13.5 · Higher only

    Why does steady direct current not maintain a transformer output?

    Answer:
    After the initial change, its magnetic field is steady, so no continuing secondary voltage is induced.
  19. Question 19 · Spec P13.5 · Higher only

    How does a shared magnetic core help the transformer?

    Answer:
    It guides the changing magnetic field so it links both circuits effectively.
  20. Question 20 · Spec P13.6 · Higher only

    What type of voltage can a transformer change continuously?

    Answer:
    An alternating voltage.
  21. Question 21 · Spec P13.9

    What does a step-up transformer do in the National Grid?

    Answer:
    It raises the voltage for transmission from the power station.
  22. Question 22 · Spec P13.9

    What does a step-down transformer do in the National Grid?

    Answer:
    It lowers voltage nearer consumers to suitable distribution or domestic levels.
  23. Question 23 · Spec P13.9

    Why is a step-up transformer placed before long transmission lines?

    Answer:
    High voltage allows a lower current for a given transmitted power.
  24. Question 24 · Spec P13.9

    Why reduce voltage before supplying homes?

    Answer:
    Transmission voltages are unsuitable and hazardous for ordinary domestic appliances.
  25. Question 25 · Spec P13.8

    Why does high transmission voltage reduce energy losses?

    Answer:
    For a fixed power it lowers current, reducing resistive heating in the lines.
  26. Question 26 · Spec P13.8

    Which equation explains lower current at higher voltage for the same power?

    Answer:
    P = VI, so I = P/V.
  27. Question 27 · Spec P13.8

    Which equation links cable heating power to current?

    Answer:
    P_loss = I²R.
  28. Question 28 · Spec P13.8

    At fixed transmitted power, what happens to current if voltage doubles?

    Answer:
    Current halves.
  29. Question 29 · Spec P13.8

    If cable current halves at fixed resistance, what happens to heating power?

    Answer:
    It becomes one-quarter, because loss is proportional to current squared.
  30. Question 30 · Spec P13.8

    Why does reducing line loss improve transmission efficiency?

    Answer:
    A greater fraction of the supplied energy reaches consumers usefully.
  31. Question 31 · Spec P13.8

    Find current when 100,000 W is transmitted at 10,000 V.

    Answer:
    I = P/V = 100,000/10,000 = 10 A.
  32. Question 32 · Spec P13.8

    Find cable heating power for 10 A through 2 Ω.

    Answer:
    P_loss = 10² × 2 = 200 W.
  33. Question 33 · Spec P13.8

    The same 100,000 W is sent at 1,000 V. Find current.

    Answer:
    I = 100,000/1,000 = 100 A.
  34. Question 34 · Spec P13.8

    For 100 A through the same 2 Ω cable, find heating power.

    Answer:
    100² × 2 = 20,000 W, much greater than at 10 A.
  35. Question 35 · Spec P13.8

    Why is comparing transmission at the same supplied power important?

    Answer:
    Otherwise changes in power demand could confuse the effect of voltage on current and losses.
  36. Question 36 · Spec P13.10

    State the ideal-transformer power equation.

    Answer:
    VpIp = VsIs: primary input power equals secondary output power for 100% efficiency.
  37. Question 37 · Spec P13.10

    Does an ideal transformer create extra energy when it raises voltage?

    Answer:
    No. Output current decreases so output power equals input power.
  38. Question 38 · Spec P13.10

    A primary uses 230 V and 2 A. Find ideal secondary power.

    Answer:
    230 × 2 = 460 W.
  39. Question 39 · Spec P13.10

    An ideal transformer supplies 460 W at 46 V. Find secondary current.

    Answer:
    Is = 460/46 = 10 A.
  40. Question 40 · Spec P13.10

    A secondary provides 12 V at 5 A. Find ideal input power.

    Answer:
    12 × 5 = 60 W.
  41. Question 41 · Spec P13.10

    An ideal transformer outputs 60 W with 240 V primary voltage. Find primary current.

    Answer:
    Ip = 60/240 = 0.25 A.
  42. Question 42 · Spec P13.10

    A primary takes 120 V at 0.50 A and the secondary current is 3 A. Find secondary voltage.

    Answer:
    Vs = (120 × 0.50)/3 = 20 V.
  43. Question 43 · Spec P13.10

    An ideal secondary supplies 400 V at 0.20 A. If primary current is 2 A, find primary voltage.

    Answer:
    Vp = (400 × 0.20)/2 = 40 V.
  44. Question 44 · Spec P13.10

    For an ideal transformer, voltage rises by factor five. How does current change?

    Answer:
    Secondary current is one-fifth of primary current, preserving power.
  45. Question 45 · Spec P13.10

    For an ideal transformer, voltage falls by factor four. How does current change?

    Answer:
    Secondary current is four times primary current.
  46. Question 46 · Spec P13.10

    An ideal transformer has 500 W input and 250 V output. Find output current.

    Answer:
    500/250 = 2.0 A.
  47. Question 47 · Spec P13.10

    Why can real output power be lower than VpIp?

    Answer:
    Some input energy is dissipated, so a real transformer can be less than 100% efficient.
  48. Question 48 · Spec P13.8

    A transmission system supplies 50 kW and loses 2 kW. Find energy-transfer efficiency.

    Answer:
    Useful power = 48 kW; efficiency = 48/50 = 96%.
  49. Question 49 · Spec P13.9

    Why are several voltage-changing stages used rather than one voltage everywhere?

    Answer:
    High voltage suits efficient long-distance transfer, while lower voltages suit local distribution and safe practical use.
  50. Question 50 · Spec P13.8

    What should a Grid design evaluation compare?

    Answer:
    Transmission losses, voltage suitability, infrastructure cost and reliability, using the provided evidence.

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