Edexcel GCSE Maths · A17–A22

Solving equations and inequalities

50 maths questions with worked answers with answers for A17–A22 Solving equations and inequalities in Edexcel GCSE Maths (spec 1MA1). Practise with flashcards, a topic quiz, a random quiz across the course, 5 crosswords, or read every question and answer below. Not official Pearson material.

All 50 questions and answers

  1. Question 1 · Linear equations · A17

    Solve 5x + 3 = 28.

    Answer:
    5x = 25.
    x = 5.
  2. Question 2 · Linear equations · A17

    Solve 4(x − 2) = 20.

    Answer:
    x − 2 = 5.
    x = 7.
  3. Question 3 · Linear equations · A17

    Solve 7x − 4 = 3x + 16.

    Answer:
    4x = 20.
    x = 5.
  4. Question 4 · Linear equations · A17

    Solve x3 + 2 = 9.

    Answer:
    x3 = 7.
    x = 21.
  5. Question 5 · Linear equations · A17

    Solve 2x + 15 = 3.

    Answer:
    2x + 1 = 15.
    2x = 14, so x = 7.
  6. Question 6 · Linear equations · A17 · Higher only

    Solve x + 12 + x − 23 = 4.

    Answer:
    Multiply by 6: 3(x + 1) + 2(x − 2) = 24.
    5x − 1 = 24, so x = 5.
  7. Question 7 · Forming equations · A17

    The angles of a triangle are x, 2x and 3x. Find x.

    Answer:
    x + 2x + 3x = 180.
    6x = 180, so x = 30°.
  8. Question 8 · Forming equations · A17

    A rectangle has length 2x + 3 and width x. Its perimeter is 36. Find x.

    Answer:
    2(2x + 3) + 2x = 36, so 6x + 6 = 36.
    x = 5.
  9. Question 9 · Quadratics · A18

    Solve x² + 5x + 6 = 0.

    Answer:
    (x + 2)(x + 3) = 0.
    x = −2 or x = −3.
  10. Question 10 · Quadratics · A18

    Solve x² − 4x = 0.

    Answer:
    x(x − 4) = 0.
    x = 0 or x = 4.
  11. Question 11 · Quadratics · A18

    Solve x² − 7x + 10 = 0.

    Answer:
    (x − 2)(x − 5) = 0.
    x = 2 or x = 5.
  12. Question 12 · Quadratics · A18 · Higher only

    Solve 2x² + x − 6 = 0.

    Answer:
    (2x − 3)(x + 2) = 0.
    x = 1.5 or x = −2.
  13. Question 13 · Quadratic formula · A18 · Higher only

    Solve x² + 4x − 3 = 0, giving answers to 2 d.p.

    Answer:
    x = −4 ± √(16 + 12)2 = −4 ± √282.
    x = 0.65 or x = −4.65.
  14. Question 14 · Quadratic formula · A18 · Higher only

    Solve 3x² − 5x − 1 = 0 to 2 d.p.

    Answer:
    x = 5 ± √(25 + 12)6 = 5 ± √376.
    x = 1.85 or x = −0.18.
  15. Question 15 · Completing the square · A18 · Higher only

    Solve x² + 6x − 4 = 0 by completing the square. Leave your answer in surd form.

    Answer:
    (x + 3)² − 13 = 0, so (x + 3)² = 13.
    x = −3 ± √13.
  16. Question 16 · Discriminant · A18 · Higher only

    How many real solutions does x² + 2x + 5 = 0 have?

    Answer:
    b² − 4ac = 4 − 20 = −16.
    It is negative, so there are no real solutions.
  17. Question 17 · Forming quadratics · A18 · Higher only

    A rectangle has width x and length x + 3. Its area is 40. Find x.

    Answer:
    x(x + 3) = 40, so x² + 3x − 40 = 0.
    (x + 8)(x − 5) = 0; length cannot be negative, so x = 5.
  18. Question 18 · Simultaneous equations · A19

    Solve x + y = 10 and x − y = 4.

    Answer:
    Add: 2x = 14, so x = 7.
    y = 3.
  19. Question 19 · Simultaneous equations · A19

    Solve 3x + 2y = 16 and x + 2y = 8.

    Answer:
    Subtract: 2x = 8, so x = 4.
    4 + 2y = 8, so y = 2.
  20. Question 20 · Simultaneous equations · A19

    Solve 2x + 3y = 13 and 5x − y = 7.

    Answer:
    Multiply the second by 3: 15x − 3y = 21. Add: 17x = 34, so x = 2.
    10 − y = 7, so y = 3.
  21. Question 21 · Simultaneous equations · A19

    2 apples and 3 pears cost £1.30. 2 apples and 1 pear cost 70p. Find the cost of a pear.

    Answer:
    Subtract: 2 pears cost 60p.
    A pear costs 30p.
  22. Question 22 · Simultaneous equations · A19 · Higher only

    Solve y = x + 1 and x² + y² = 13.

    Answer:
    x² + (x + 1)² = 13, so 2x² + 2x − 12 = 0, x² + x − 6 = 0.
    (x + 3)(x − 2) = 0: x = 2, y = 3 or x = −3, y = −2.
  23. Question 23 · Simultaneous equations · A19 · Higher only

    Solve y = x² and y = 2x + 3.

    Answer:
    x² = 2x + 3, so x² − 2x − 3 = 0, (x − 3)(x + 1) = 0.
    x = 3, y = 9 or x = −1, y = 1.
  24. Question 24 · Iteration · A20 · Higher only

    Use xₙ₊₁ = √(2xₙ + 5) with x₀ = 3 to find x₁ and x₂ to 3 d.p.

    Answer:
    x₁ = √11 = 3.317.
    x₂ = √(2 × 3.3166 + 5) = √11.633 = 3.411.
  25. Question 25 · Iteration · A20 · Higher only

    Show that x³ − 4x − 1 = 0 has a root between 2 and 3.

    Answer:
    When x = 2: 8 − 8 − 1 = −1. When x = 3: 27 − 12 − 1 = 14.
    The sign changes, so there is a root between 2 and 3.
  26. Question 26 · Iteration · A20 · Higher only

    Show that x² − 3x − 1 = 0 can be rearranged to x = 3 + 1x.

    Answer:
    x² = 3x + 1.
    Divide by x: x = 3 + 1x.
  27. Question 27 · Forming equations · A21

    I think of a number, double it and add 9. The result is 25. Find the number.

    Answer:
    2n + 9 = 25.
    2n = 16, so n = 8.
  28. Question 28 · Forming equations · A21

    Tom is 4 years older than Sara. Their ages add up to 30. How old is Sara?

    Answer:
    s + (s + 4) = 30.
    2s = 26, so Sara is 13.
  29. Question 29 · Interpreting · A21

    A solution to a quadratic for the length of a side is x = −6. Why is it rejected?

    Answer:
    A length cannot be negative.
    Only the positive solution makes sense.
  30. Question 30 · Inequalities · A22

    Solve 3x − 5 > 10.

    Answer:
    3x > 15.
    x > 5.
  31. Question 31 · Inequalities · A22

    Solve 2(x + 3) ≤ 14.

    Answer:
    x + 3 ≤ 7.
    x ≤ 4.
  32. Question 32 · Inequalities · A22

    List the integers n such that −2 < n ≤ 3.

    Answer:
    −2 is not included; 3 is included.
    −1, 0, 1, 2, 3.
  33. Question 33 · Inequalities · A22

    Solve −3 ≤ 2x + 1 < 7.

    Answer:
    Subtract 1: −4 ≤ 2x < 6.
    −2 ≤ x < 3.
  34. Question 34 · Inequalities · A22

    Solve 5 − 2x > 11.

    Answer:
    −2x > 6.
    Dividing by a negative reverses the sign: x < −3.
  35. Question 35 · Number lines · A22

    On a number line, what does an open circle at 4 mean?

    Answer:
    4 is not included.
    It shows < or >.
  36. Question 36 · Quadratic inequalities · A22 · Higher only

    Solve x² − 9 < 0.

    Answer:
    The roots are x = ±3; the graph is below the axis between them.
    −3 < x < 3.
  37. Question 37 · Quadratic inequalities · A22 · Higher only

    Solve x² − 5x + 4 ≥ 0.

    Answer:
    (x − 1)(x − 4) ≥ 0. The graph is above the axis outside the roots.
    x ≤ 1 or x ≥ 4.
  38. Question 38 · Regions · A22 · Higher only

    Which side of y = 2x + 1 is the region y > 2x + 1?

    Answer:
    Test (0, 0): 0 > 1 is false.
    The region above the line, not containing the origin.
  39. Question 39 · Regions · A22 · Higher only

    When shading a region, when is the boundary line dashed?

    Answer:
    For strict inequalities.
    Use a dashed line for < or >, and a solid line for ≤ or ≥.
  40. Question 40 · Linear equations · A17

    Solve 9 − 2x = 3.

    Answer:
    −2x = −6.
    x = 3.
  41. Question 41 · Linear equations · A17

    Solve 3(2x + 1) = 2(x + 9).

    Answer:
    6x + 3 = 2x + 18.
    4x = 15, so x = 3.75.
  42. Question 42 · Simultaneous equations · A19

    Solve y = 2x − 1 and y = x + 3.

    Answer:
    2x − 1 = x + 3.
    x = 4, y = 7.
  43. Question 43 · Quadratics · A18

    Solve x² = 64.

    Answer:
    Take square roots, remembering both signs.
    x = 8 or x = −8.
  44. Question 44 · Quadratics · A18 · Higher only

    Solve (x − 2)² = 25.

    Answer:
    x − 2 = ±5.
    x = 7 or x = −3.
  45. Question 45 · Inequalities · A22

    Write down the largest integer x that satisfies 4x < 23.

    Answer:
    x < 5.75.
    x = 5.
  46. Question 46 · Forming equations · A21 · Higher only

    A square has side x + 2 and area 49. Find x.

    Answer:
    (x + 2)² = 49, so x + 2 = 7 (side must be positive).
    x = 5.
  47. Question 47 · Linear equations · A17

    Solve 0.5x + 3 = 8.

    Answer:
    0.5x = 5.
    x = 10.
  48. Question 48 · Simultaneous equations · A19 · Higher only

    Solve 4x + 3y = 1 and 3x − 2y = 5.

    Answer:
    ×2 and ×3: 8x + 6y = 2 and 9x − 6y = 15. Add: 17x = 17, x = 1.
    4 + 3y = 1, so y = −1.
  49. Question 49 · Iteration · A20 · Higher only

    Why is iteration used to solve some equations?

    Answer:
    Some equations cannot be solved exactly by algebra.
    Iteration gives an approximate solution to any accuracy required.
  50. Question 50 · Inequalities · A22

    Solve 4x + 1 ≥ 2x − 9.

    Answer:
    2x ≥ −10.
    x ≥ −5.

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