Graphs
50 maths questions with worked answers with answers for A8–A16 Graphs in Edexcel GCSE Maths (spec 1MA1). Practise with flashcards, a topic quiz, a random quiz across the course, 5 crosswords, or read every question and answer below. Not official Pearson material.
All 50 questions and answers
Question 1 · Coordinates · A8
Find the midpoint of (2, 7) and (8, −1).
Answer:Average the x-values: 2 + 82 = 5. Average the y-values: 7 + (−1)2 = 3.
Midpoint (5, 3).Question 2 · Coordinates · A8
The midpoint of AB is (4, 6). A is (1, 2). Find B.
Answer:From A to the midpoint: +3 in x and +4 in y.
B = (4 + 3, 6 + 4) = (7, 10).Question 3 · Gradient · A9
Find the gradient of the line through (1, 3) and (5, 11).
Answer:Gradient = change in ychange in x = 11 − 35 − 1.
84 = 2.Question 4 · Gradient · A9
Find the gradient of the line through (−2, 5) and (4, −7).
Answer:−7 − 54 − (−2) = −126.
−2.Question 5 · Straight lines · A9
Write the gradient and y-intercept of y = 5x − 3.
Answer:Compare with y = mx + c.
Gradient 5, y-intercept (0, −3).Question 6 · Straight lines · A9
Find the gradient and y-intercept of 2y + 6x = 8.
Answer:Rearrange: 2y = −6x + 8, so y = −3x + 4.
Gradient −3, y-intercept (0, 4).Question 7 · Equation of a line · A9
Find the equation of the line with gradient 4 through (2, 5).
Answer:y = 4x + c. Substitute: 5 = 8 + c, so c = −3.
y = 4x − 3.Question 8 · Equation of a line · A9
Find the equation of the line through (1, 2) and (3, 8).
Answer:Gradient = 8 − 23 − 1 = 3. 2 = 3 + c, so c = −1.
y = 3x − 1.Question 9 · Parallel lines · A9
Write the equation of a line parallel to y = 2x + 1 passing through (0, −4).
Answer:Parallel lines have the same gradient, 2.
y = 2x − 4.Question 10 · Perpendicular lines · A9 · Higher only
Find the gradient of a line perpendicular to y = 23x + 1.
Answer:Perpendicular gradients multiply to −1.
−32.Question 11 · Perpendicular lines · A9 · Higher only
Find the equation of the line perpendicular to y = 4x − 2 through (8, 1).
Answer:Gradient = −14. 1 = −14 × 8 + c, so 1 = −2 + c, c = 3.
y = −14x + 3.Question 12 · Graphs · A9
Where does the line y = 3x − 6 cross the x-axis?
Answer:On the x-axis, y = 0: 3x − 6 = 0.
x = 2, so (2, 0).Question 13 · Roots and intercepts · A10
Write the coordinates of where y = x² − 9 crosses the axes.
Answer:y-axis: x = 0 gives y = −9. x-axis: x² = 9.
(0, −9), (3, 0) and (−3, 0).Question 14 · Turning points · A11 · Higher only
Write x² − 6x + 11 in the form (x − a)² + b.
Answer:(x − 3)² = x² − 6x + 9.
(x − 3)² + 2.Question 15 · Turning points · A11 · Higher only
Use completing the square to find the turning point of y = x² + 8x + 3.
Answer:(x + 4)² − 16 + 3 = (x + 4)² − 13.
Turning point (−4, −13), a minimum.Question 16 · Quadratic graphs · A11
Describe the shape of the graph of y = −x² + 4.
Answer:The coefficient of x² is negative.
An n-shaped parabola with a maximum at (0, 4).Question 17 · Quadratic graphs · A11
The roots of a quadratic are x = 1 and x = 5. Find the x-coordinate of the turning point.
Answer:The turning point lies halfway between the roots.
x = 1 + 52 = 3.Question 18 · Graph shapes · A12
What shape is the graph of y = x³?
Answer:A cubic curve.
It rises from bottom left, flattens through the origin and rises to the top right.Question 19 · Graph shapes · A12
Describe the graph of y = 1x.
Answer:A reciprocal graph.
Two separate curves in opposite quadrants; it never touches either axis.Question 20 · Graph shapes · A12 · Higher only
Sketch the key features of y = 2ˣ.
Answer:It passes through (0, 1).
It rises steeply for positive x and approaches the x-axis for negative x without touching it.Question 21 · Trig graphs · A12 · Higher only
State the maximum value and period of y = sin x.
Answer:sin x varies between −1 and 1.
Maximum 1; period 360°.Question 22 · Trig graphs · A12 · Higher only
For 0° ≤ x ≤ 360°, where does y = cos x cross the x-axis?
Answer:cos x = 0.
At x = 90° and x = 270°.Question 23 · Trig graphs · A12 · Higher only
Given sin 30° = 0.5, find another angle between 0° and 360° with sine 0.5.
Answer:Use the symmetry of the sine graph: 180° − 30°.
150°.Question 24 · Transformations · A13 · Higher only
Describe the transformation that maps y = f(x) to y = f(x) + 3.
Answer:3 is added to every y-value.
Translation by 03.Question 25 · Transformations · A13 · Higher only
Describe the transformation that maps y = f(x) to y = f(x − 2).
Answer:The graph moves 2 units in the positive x-direction.
Translation by 20.Question 26 · Transformations · A13 · Higher only
Describe the transformation that maps y = f(x) to y = −f(x).
Answer:Every y-value changes sign.
Reflection in the x-axis.Question 27 · Transformations · A13 · Higher only
Describe the transformation that maps y = f(x) to y = f(−x).
Answer:Every x-value changes sign.
Reflection in the y-axis.Question 28 · Transformations · A13 · Higher only
y = x² has turning point (0, 0). State the turning point of y = (x + 5)² − 1.
Answer:Translation by −5−1.
(−5, −1).Question 29 · Real-life graphs · A14
On a distance–time graph, what does the gradient represent?
Answer:Distance ÷ time.
Speed.Question 30 · Real-life graphs · A14
On a distance–time graph, what does a horizontal line show?
Answer:Distance is not changing.
The object is stationary.Question 31 · Real-life graphs · A14
A taxi charges £3 plus £2 per mile. Write a formula for the cost C of m miles.
Answer:Fixed charge £3, plus 2 for each mile.
C = 2m + 3.Question 32 · Real-life graphs · A14
In the formula C = 2m + 3, what does the 3 represent on the graph?
Answer:It is the y-intercept.
The fixed charge of £3 before any miles are travelled.Question 33 · Real-life graphs · A14
A car travels 120 km in the first 2 hours. Find its speed from the graph's gradient.
Answer:Gradient = 1202.
60 km/h.Question 34 · Velocity–time graphs · A15 · Higher only
On a velocity–time graph, what does the area under the graph represent?
Answer:Velocity × time.
Distance travelled.Question 35 · Velocity–time graphs · A15 · Higher only
On a velocity–time graph, what does the gradient represent?
Answer:Change in velocity ÷ time.
Acceleration.Question 36 · Velocity–time graphs · A15 · Higher only
A car accelerates uniformly from 0 to 20 m/s in 8 seconds. Find the distance travelled.
Answer:The area under the graph is a triangle.
12 × 8 × 20 = 80 m.Question 37 · Rates of change · A15 · Higher only
How do you estimate the gradient of a curve at a point?
Answer:Draw a tangent to the curve at that point.
Find the gradient of the tangent: change in y ÷ change in x.Question 38 · Area under a curve · A15 · Higher only
How can you estimate the area under a curve?
Answer:Split the area into trapezia (or strips).
Add the areas of the shapes.Question 39 · Circles · A16 · Higher only
Write the equation of the circle with centre (0, 0) and radius 6.
Answer:x² + y² = r².
x² + y² = 36.Question 40 · Circles · A16 · Higher only
Find the radius of x² + y² = 50.
Answer:r² = 50.
r = √50 = 5√2.Question 41 · Circles · A16 · Higher only
Show that (3, 4) lies on x² + y² = 25.
Answer:3² + 4² = 9 + 16.
= 25, so the point lies on the circle.Question 42 · Circles · A16 · Higher only
Find the gradient of the tangent to x² + y² = 25 at (3, 4).
Answer:Gradient of radius = 43. The tangent is perpendicular.
Gradient = −34.Question 43 · Circles · A16 · Higher only
Find the equation of the tangent to x² + y² = 25 at (3, 4).
Answer:Gradient −34: y − 4 = −34(x − 3).
y = −34x + 254 (or 3x + 4y = 25).Question 44 · Solving graphically · A10 · Higher only
How can you use a graph to solve x² − 2x − 3 = 0?
Answer:Plot y = x² − 2x − 3.
Read off the x-values where the curve crosses the x-axis (x = −1 and x = 3).Question 45 · Solving graphically · A10
How do you use graphs to solve a pair of simultaneous equations?
Answer:Draw both lines on the same axes.
The solution is the point where they intersect.Question 46 · Straight lines · A9
Does the point (3, 10) lie on y = 4x − 2?
Answer:4 × 3 − 2 = 10.
Yes.Question 47 · Graph shapes · A12
Which graph is a straight line: y = 3x + 1, y = x² or y = 1x?
Answer:Only linear equations give straight lines.
y = 3x + 1.Question 48 · Coordinates · A8
Which quadrant contains the point (−3, 5)?
Answer:Negative x, positive y.
The second quadrant (top left).Question 49 · Straight lines · A9
What is the equation of the x-axis?
Answer:Every point on it has y-coordinate 0.
y = 0.Question 50 · Quadratic graphs · A11
Find the y-intercept of y = x² − 5x + 6.
Answer:Substitute x = 0.
(0, 6).
More Edexcel GCSE Maths topics
- N1–N9 Structure and calculation
- N10–N12 Fractions, decimals and percentages
- N13–N16 Measures and accuracy
- A1–A7 Notation, vocabulary and manipulation
- A8–A16 Graphs
- A17–A22 Solving equations and inequalities
- A23–A25 Sequences
- R1–R16 Ratio, proportion and rates of change
- G1–G15 Properties and constructions
- G16–G23 Mensuration and calculation
- G24–G25 Vectors
- P1–P9 Probability
- S1–S6 Statistics
Other Maths courses: AQA GCSE Maths, OCR GCSE Maths.
