Vectors
50 maths questions with worked answers with answers for 3.4.3 Vectors in AQA GCSE Maths (spec 8300). Practise with flashcards, a topic quiz, a random quiz across the course, 5 crosswords, or read every question and answer below. Not official AQA material.
All 50 questions and answers
Question 1 · Translation · G24
What translation is represented by the vector 3−2?
Answer:The top component 3 means 3 units right.
The bottom component −2 means 2 units down.Question 2 · Translation · G24
Write the vector for 4 units left and 5 units up.
Answer:4 units left gives horizontal component −4.
5 units up gives vertical component 5.
The vector is −45.Question 3 · Translation · G24
Translate (2, 1) by 3−4.
Answer:Add horizontal components: 2 + 3 = 5.
Add vertical components: 1 − 4 = −3.
The image is (5, −3).Question 4 · Translation · G24
Translate (−1, 6) by −23.
Answer:Add horizontal components: −1 − 2 = −3.
Add vertical components: 6 + 3 = 9.
The image is (−3, 9).Question 5 · Translation · G24
Find the vector that maps (1, 2) to (5, −1).
Answer:Horizontal change = 5 − 1 = 4.
Vertical change = −1 − 2 = −3.
The vector is 4−3.Question 6 · Translation · G24
Find the image of (0, −3) under translation −52.
Answer:Horizontal coordinate: 0 − 5 = −5.
Vertical coordinate: −3 + 2 = −1.
The image is (−5, −1).Question 7 · Translation · G24
A point moves from (−3, 4) to (2, 4). Give the translation vector.
Answer:Horizontal change = 2 − (−3) = 5.
Vertical change = 4 − 4 = 0.
The vector is 50.Question 8 · Translation · G24
Find the translation taking (7, 2) to (−1, −2).
Answer:Horizontal change = −1 − 7 = −8.
Vertical change = −2 − 2 = −4.
The vector is −8−4.Question 9 · Translation · G24
A point is translated by 06. Describe its movement.
Answer:The horizontal component is 0, so there is no horizontal movement.
The vertical component is 6, so move 6 units up.Question 10 · Translation · G24
A point at (3, −2) is translated to (0, 5). Give the vector.
Answer:Horizontal change = 0 − 3 = −3.
Vertical change = 5 − (−2) = 7.
The vector is −37.Question 11 · Components · G25
If a = 25 and b = 3−1, find a + b.
Answer:Add horizontal components: 2 + 3 = 5.
Add vertical components: 5 + (−1) = 4.
a + b = 54.Question 12 · Components · G25
If a = 62 and b = 15, find a − b.
Answer:Subtract corresponding components: 6 − 1 = 5 and 2 − 5 = −3.
a − b = 5−3.Question 13 · Components · G25
If a = −24, find 3a.
Answer:Multiply both components by 3: 3 × (−2) = −6 and 3 × 4 = 12.
3a = −612.Question 14 · Components · G25
If b = 8−6, find b2.
Answer:Divide both components by 2: 8 ÷ 2 = 4 and −6 ÷ 2 = −3.
b2 = 4−3.Question 15 · Components · G25
If a = 37, find −a.
Answer:Multiply each component by −1.
−a = −3−7.Question 16 · Components · G25
Calculate 4−2 + −18.
Answer:Add corresponding components: 4 + (−1) = 3 and −2 + 8 = 6.
The result is 36.Question 17 · Components · G25
Calculate −34 − 2−5.
Answer:Subtract corresponding components: −3 − 2 = −5 and 4 − (−5) = 9.
The result is −59.Question 18 · Components · G25
Calculate 21−3 + 45.
Answer:Double the first vector to get 2−6.
Add components: 2 + 4 = 6 and −6 + 5 = −1.
The result is 6−1.Question 19 · Components · G25
Calculate 321 − 214.
Answer:Multiply components: 321 = 63 and 214 = 28.
Subtract to get 4−5.Question 20 · Components · G25
Find x if x3 + 2−1 = 72.
Answer:Equate horizontal components: x + 2 = 7.
Subtract 2: x = 5.Question 21 · Components · G25
Find y if 4y − 12 = 36.
Answer:Equate vertical components: y − 2 = 6.
Add 2: y = 8.Question 22 · Components · G25
Find a if 2a = 10−4.
Answer:Divide each component of 2a by 2: 10 ÷ 2 = 5 and −4 ÷ 2 = −2.
a = 5−2.Question 23 · Components · G25
Which vector reverses 5−7?
Answer:Reverse a vector by multiplying each component by −1.
The reverse is −57.Question 24 · Components · G25
Find the magnitude of 34.
Answer:Use Pythagoras: magnitude² = 3² + 4² = 25.
Magnitude = √25 = 5.Question 25 · Components · G25
Find the magnitude of −512.
Answer:Use Pythagoras: magnitude² = (−5)² + 12² = 169.
Magnitude = √169 = 13.Question 26 · Position vectors · G25
A has position vector 23 and B has position vector 79. Find vector AB.
Answer:Vector AB = position vector of B − position vector of A.
Subtract components: 7 − 2 = 5 and 9 − 3 = 6.
Vector AB = 56.Question 27 · Position vectors · G25
A = (−1, 4) and B = (3, −2). Find vector AB.
Answer:Vector AB = position vector of B − position vector of A.
Components: 3 − (−1) = 4 and −2 − 4 = −6.
Vector AB = 4−6.Question 28 · Position vectors · G25
A = (4, 5) and B = (−2, 1). Find vector BA.
Answer:Vector BA = position vector of A − position vector of B.
Components: 4 − (−2) = 6 and 5 − 1 = 4.
Vector BA = 64.Question 29 · Position vectors · G25
If vector OA = 3−1 and vector AB = 24, find vector OB.
Answer:Follow the path from O to A to B: vector OB = vector OA + vector AB.
Components: 3 + 2 = 5 and −1 + 4 = 3.
Vector OB = 53.Question 30 · Position vectors · G25
If vector OA = 82 and vector AB = −35, find vector OB.
Answer:Follow the path from O to A to B: vector OB = vector OA + vector AB.
Components: 8 − 3 = 5 and 2 + 5 = 7.
Vector OB = 57.Question 31 · Position vectors · G25
If vector OB = 96 and vector AB = 42, find vector OA.
Answer:Vector OA = vector OB − vector AB.
Components: 9 − 4 = 5 and 6 − 2 = 4.
Vector OA = 54.Question 32 · Position vectors · G25
Find the midpoint of A(2, 6) and B(8, 10).
Answer:Average the x-coordinates: (2 + 8) ÷ 2 = 5.
Average the y-coordinates: (6 + 10) ÷ 2 = 8.
Midpoint = (5, 8).Question 33 · Position vectors · G25
Find the midpoint of A(−4, 2) and B(2, −6).
Answer:Average the x-coordinates: (−4 + 2) ÷ 2 = −1.
Average the y-coordinates: (2 − 6) ÷ 2 = −2.
Midpoint = (−1, −2).Question 34 · Position vectors · G25
P is halfway from A to B. If vector AB = 86, find vector AP.
Answer:Halfway means vector AP is half of vector AB.
8 ÷ 2 = 4 and 6 ÷ 2 = 3, so vector AP = 43.Question 35 · Position vectors · G25
If vector AB = 3−4, find vector BA.
Answer:The reverse vector is found by changing both component signs.
Vector BA = −34.Question 36 · Paths · G25
If vector AB = a and vector BC = b, express vector AC.
Answer:Follow the path A to B to C.
Vector AC = vector AB + vector BC = a + b.Question 37 · Paths · G25
If vector AB = a and vector AC = b, express vector BC.
Answer:Follow B to A to C: vector BC = vector BA + vector AC.
Vector BA = −a, so vector BC = −a + b = b − a.Question 38 · Paths · G25
If vector OA = a and vector OB = b, express vector AB.
Answer:Travel from A to O to B: vector AB = vector AO + vector OB.
Vector AO = −a, so vector AB = b − a.Question 39 · Paths · G25
If vector OA = a and vector AB = 2b, express vector OB.
Answer:Follow O to A to B: vector OB = vector OA + vector AB.
Therefore vector OB = a + 2b.Question 40 · Paths · G25
If vector PQ = 2a and vector QR = −a + b, express vector PR.
Answer:Follow P to Q to R: vector PR = vector PQ + vector QR.
2a + (−a + b) = a + b.Question 41 · Paths · G25
If vector AB = a and vector BC = 2a, express vector AC.
Answer:Follow A to B to C: vector AC = vector AB + vector BC.
a + 2a = 3a.Question 42 · Paths · G25
If vector AB = 3a and vector AC = a, express vector CB.
Answer:Follow C to A to B: vector CB = vector CA + vector AB.
Vector CA = −a, so vector CB = −a + 3a = 2a.Question 43 · Paths · G25
If vector AB = 41 and vector BC = −23, find vector AC.
Answer:Follow A to B to C: vector AC = vector AB + vector BC.
Add components: 4 + (−2) = 2 and 1 + 3 = 4.
Vector AC = 24.Question 44 · Paths · G25
If vector PQ = 64 and vector PR = 1−2, find vector QR.
Answer:Vector QR = vector PR − vector PQ.
Components: 1 − 6 = −5 and −2 − 4 = −6.
Vector QR = −5−6.Question 45 · Parallel · G25 · Higher only
Are vectors 23 and 69 parallel? Explain.
Answer:Multiply both components of 23 by 3 to get 69.
One vector is a scalar multiple of the other, so they are parallel.Question 46 · Parallel · G25 · Higher only
Are vectors 2−1 and −42 parallel? Explain.
Answer:Multiply both components of 2−1 by −2 to get −42.
They are parallel and point in opposite directions.Question 47 · Parallel · G25 · Higher only
Find k so 36 and k10 are parallel.
Answer:The scale factor from 6 to 10 is 106 = 53.
Apply it to the top component: k = 3 × 53 = 5.Question 48 · Geometric proof · G25 · Higher only
Vector OA = a and vector OB = b. M is the midpoint of segment AB. Express vector OM.
Answer:Vector OM = vector OA + half of vector AB.
Vector AB = b − a, so vector OM = a + b − a2.
Simplify: vector OM = a + b2.Question 49 · Geometric proof · G25 · Higher only
If vector AB = a and vector CD = 2a, what can you conclude about these directed segments?
Answer:Vector CD is the positive scalar multiple 2a of vector AB.
For nonzero a, the segments are parallel in the same direction and CD is twice as long.Question 50 · Geometric proof · G25 · Higher only
If vector OP = a, vector OQ = 3a and a is nonzero, what can you conclude about O, P and Q?
Answer:Vector OQ = 3 times vector OP and a is nonzero.
The points O, P and Q are collinear; P is one-third of the way from O to Q.
More AQA GCSE Maths topics
- 3.1.1 Structure and calculation
- 3.1.2 Fractions, decimals and percentages
- 3.1.3 Measures and accuracy
- 3.2.1 Notation, vocabulary and manipulation
- 3.2.2 Graphs
- 3.2.3 Solving equations and inequalities
- 3.2.4 Sequences
- 3.3 Ratio, proportion and rates of change
- 3.4.1 Properties and constructions
- 3.4.2 Mensuration and calculation
- 3.4.3 Vectors
- 3.5 Probability
- 3.6 Statistics
Other Maths courses: Edexcel GCSE Maths, OCR GCSE Maths.
